[ROVERNET - UK] Battery in Boot?

Richard Elliott relliott44 at yahoo.com
Sat Sep 11 08:25:16 BST 2004

Hi Eric,

One thing about electronics and electrical- there's
probably a formula and a code.

For the battery relocation issue, there will
definitely be a voltage drop for a given wire
diameter, and there is also the allowable drop
percentage to consider, which is addressed in U.S. in
the NEC as 2%.  Any figure for voltage drop has to be
considerate of current 'I' (constant current), length
'L' and voltage 'V'.  Putting everything together, a
figure for 'Circular mils' CM (wire diameter) is
CM = (25 x I x L) / V 

Richard Elliott
1970 NADA P6B Tobacco Leaf

--- Eric Russell <p6rovers at yahoo.com> wrote:

> Tom,
> My first career involved installing RADAR and depth
> sounders on both deep sea ships, tug boats, and
> fishing boats.  The small craft were fitted with a
> small AC generator run by the boats' DC batteries. 
> It
> was always our objective to get the generator as
> close
> as we could to the batteries to avoid voltage loss. 
> I
> have now forgotten the mathematic formula to
> calculate
> the voltage drop for a length of wire based upon its
> diameter.  Perhaps somebody can help with that.
> I think it creates another variable for you with
> regard to starting power but I thought I should give
> you a caution rather than just reading and moving
> on.
> Eric
> =====
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